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jAvA两个二维数组相加

int[][] list1 = {{1, 2, 3}, {1, 2, 3}, {1, 2, 3}}; int[][] list2 = {{1, 2, 3}, {1, 2, 3}, {1, 2, 3}}; int[][] result = new int[3][3]; for(int i=0; i

public int sum(int[][] a2){ int sum = 0; for(int i=0;i

import java.util.Scanner; public class C{ public static void main(String args[]){ Scanner in = new Scanner(System.in); System.out.print("请输入二维数组x的行数:"); int a = in.nextInt(); System.out.print("请输入二维数组x的列数:...

二维数组的话,必须循环行和列,之后求总和即可: public class Test { public static void main(String args[]) throws ParseException { int [][]a = {{1,2,4,5},{6,7,8,9},{10,11,12,13},{14,15,16,17}}; int sum =0; //设置sum为0,方便计算...

使用嵌套for循环

package retestC8;public class Summation { public static void main(String[] args) { String str[][]=new String[][]{{"1","2"},{"3","4"},{"5","6"},{"7","8"}}; //怎样将这个二维的字符串型数组里面的数值全部加起来? int sum=0; for(int...

使用循环将值遍历进行相加 例:int[] arr={1,2,3,4,5}; int sum=0; for(int a:arr){ sum+=a; }

for(int i=0,i

以String为例的一个示例。 import java.util.*; public class Test { public static void main(String[] args) { String[][] strs1 = {{"start", "htr", "fa"}, {"543", "gfd", "gs"}, {"jh", "k", "gsk"}, {"675", "hfhgf"}}; String[][] strs2...

二维数组的话,必须循环行和列,之后求总和即可: public class Test { public static void main(String args[]) throws ParseException { int [][]a = {{1,2,4,5},{6,7,8,9},{10,11,12,13},{14,15,16,17}}; int sum =0; //设置sum为0,方便计算...

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